79x^2+x-0.1659=0

Solution for 79x^2+x-0.1659=0 equation:

79x^2+x-0.1659=0

a = 79; b = 1; c = -0.1659;
Δ = b2-4ac
Δ = 12-4·79·(-0.1659)
Δ = 53.4244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{53.4244}}{2*79}=\frac{-1-\sqrt{53.4244}}{158}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{53.4244}}{2*79}=\frac{-1+\sqrt{53.4244}}{158}
$